A) \[MnO_{4}^{-}\to M{{n}^{2+}}\]
B) \[CrO_{4}^{2-}\to C{{r}^{3+}}\]
C) \[MnO_{4}^{2-}\to Mn{{O}_{2}}\]
D) \[C{{r}_{2}}O_{7}^{2-}\to 2C{{r}^{3+}}\]
Correct Answer: A
Solution :
O.N. of \[Mn\] in \[MnO_{4}^{-}\]is \[+7\] and in \[M{{n}^{2+}}\]it is\[+2\]. The difference is of 5 electrons.
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