A) \[\frac{175}{1296}\]
B) \[\frac{275}{1296}\]
C) \[\frac{85}{1296}\]
D) \[\frac{75}{648}\]
Correct Answer: A
Solution :
[a] 4 must be obtained on at least one dice. x = number of dice on which 4 is obtained Required probability \[=P(x=1)+P(x=2)+P(x=3)+P(x=4)\] \[=\frac{^{4}{{C}_{1}}\times {{3}^{3}}}{{{6}^{4}}}+\frac{^{4}{{C}_{2}}\times {{3}^{2}}}{{{6}^{4}}}+\frac{^{4}{{C}_{3}}\times 3}{{{6}^{4}}}+\frac{1}{{{6}^{4}}}=\frac{175}{1296}\]
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