A) \[\frac{15\sqrt{3}\,m}{2}\]
B) \[\frac{40}{3}m\]
C) \[5\sqrt{3}m\]
D) \[\frac{20}{3}m\]
Correct Answer: D
Solution :
\[t=\frac{2u\sin 30{}^\circ }{g\,\cos 30{}^\circ }=\frac{2(10)\,(1/2)}{10(\sqrt{3}/2)}=\frac{2}{\sqrt{3}}\sec \] \[R=10\cos 30{}^\circ \,\,t-\frac{1}{2}\,g\sin \,30{}^\circ {{t}^{2}}\] \[=\frac{10\sqrt{3}}{2}\left( \frac{2}{\sqrt{3}} \right)-\frac{1}{2}(10)\left( \frac{1}{2} \right)\frac{4}{3}=10-\frac{10}{3}=\frac{20}{3}m\]
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