A) \[1\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) \[2\]
Correct Answer: D
Solution :
\[{{\rho }_{B}}=2{{\rho }_{A}}\] \[{{d}_{B}}=2{{d}_{A}}\] \[{{R}_{B}}={{R}_{A}}\Rightarrow \frac{{{\rho }_{B}}{{\ell }_{B}}}{{{A}_{B}}}=\frac{\rho {{.}_{A}}{{\ell }_{A}}}{{{A}_{A}}}\] \[\therefore \,\,\frac{{{\ell }_{B}}}{{{\ell }_{A}}}=\frac{{{\rho }_{A}}}{{{\rho }_{B}}}\times \frac{d_{B}^{2}}{d_{A}^{2}}=\frac{{{\rho }_{A}}}{2{{\rho }_{A}}}\times \frac{4d_{A}^{2}}{d_{A}^{2}}=2\]
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