JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    Schotten-Baumann reaction is a reaction of phenols with

    A) Benzoyl chloride and sodium hydroxide

    B) Acetyl chloride and sodium hydroxide

    C) Salicylic acid and cone. \[{{H}_{2}}S{{O}_{4}}\]

    D) Acetyl chloride and cone \[{{H}_{2}}S{{O}_{4}}\]

    Correct Answer: A

    Solution :

      The function of \[NaOH\]is To convert phenol to more stronger nucleophile \[Ph{{O}^{-}}\] (ii) To neutralize the acid formed                        


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