A) \[y/3\]
B) \[y\]
C) \[3y\]
D) \[9y\]
Correct Answer: D
Solution :
\[y\propto {{n}^{2}}\] For 1st orbit \[y=1\] For 3rd orbit \[=y\propto {{3}^{2}}=9\] So it will be 9y.
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