A) n-propyl amine
B) isopropylamine
C) ethyiamine
D) ethylmethyl amine
Correct Answer: D
Solution :
\[\underset{Ethyl\,\,bromide}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,\xrightarrow{AgCN}\underset{Ethyl\,\,isocyanide}{\mathop{{{C}_{2}}{{H}_{5}}NC}}\,\xrightarrow{\operatorname{Re}duction}\] \[\underset{\text{Ethyl}\,\,\text{methyl}\,\,\text{amine}}{\mathop{{{C}_{2}}{{H}_{5}}NHC{{H}_{3}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
