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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    A boy throws a ball upwards with velocity\[{{v}_{0}}=20\text{ }m/s\]. The wind imparts a horizontal acceleration of \[4\text{ }m/{{s}^{2}}\]to the left. The angle \[\theta \] at which the ball must be thrown so that the ball returns to the boy's hand is \[(g=10\,m/{{s}^{2}})\]

    A) \[{{\tan }^{-1}}(1.2)\]           

    B)        \[{{\tan }^{-1}}(0.2)\]

    C) \[{{\tan }^{-1}}(2)\]              

    D)       \[{{\tan }^{-1}}(0.4)\]

    Correct Answer: D

    Solution :

    [d] \[{{s}_{x}}={{v}_{0}}\sin \theta -4t=0\] \[{{v}_{0}}\sin \theta =4t\]                               ......(i) \[{{s}_{y}}={{v}_{0}}\cos \theta -10t=0\] \[{{v}_{0}}\cos \theta =10t\]                  ......(ii) From (i) &(ii), \[\tan \theta =0.4\]


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