JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    In case of a transverse wave in a string,                                                                                       
    (i) it \[\frac{\lambda }{2\pi }>{{A}_{0}},\] maximum particle speed is more than the wave speed                                                       
    (ii) if \[\frac{\lambda }{2\pi }={{A}_{0}},\] maximum particle speed is equal to the wave speed                                                        
    (iii) In harmonic wave, wave velocity is constant
    (iv) In harmonic wave, particle speed is constant
    The correct statements are

    A) (i) and (iii)

    B) (ii) and (iii)

    C) (i) and (iv)                     

    D) (ii) and (iv)

    Correct Answer: B

    Solution :

        [b] Maximum particle speed \[=\omega {{A}_{0}}\] Wave velocity \[=\left( \frac{\omega }{K} \right)\Rightarrow \frac{\omega }{K}=\omega {{A}_{0}}=\frac{\lambda }{2\pi }={{A}_{0}}\] For a medium wave, velocity is constant.    


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