then p, q, r are in:
A) AP
B) GP
C) HP
D) none of these
Correct Answer: A
Solution :
: Applying \[{{R}_{3}}\to {{R}_{3}}-{{R}_{2}}\]and \[{{R}_{2}}\to {{R}_{2}}-{{R}_{1}}\] and then \[{{C}_{1}}\to {{C}_{1}}-{{C}_{2}}\] we get
Now, on expanding along \[{{C}_{1}}\]we get \[p+r=2q\] \[\Rightarrow \]p, q,r are in AP.
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