A) \[\frac{2}{3}\]
B) \[\frac{4}{3}\]
C) \[\frac{8}{3}\]
D) \[\frac{16}{3}\]
Correct Answer: D
Solution :
Area of the region is given by \[A=\int\limits_{-1}^{3}{\left[ (y+1)-\left( \frac{{{y}^{2}}-1}{2} \right) \right]}\,dy=\frac{16}{3}\]
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