2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 14

  • question_answer
    For the reaction \[A\xrightarrow{{}}\]Product. It is found that the rate of reaction increases by a factor of \[6.25\]when concentration of A increases by a factor of\[2.5\]. Calculate the order of reaction with respect to A.

    A) 0                       

    B)   1                       

    C) 2     

    D)   3

    Correct Answer: C

    Solution :

          [c] Rate \[(r)=k{{[A]}^{n}}=k{{(X)}^{n}}\] \[6.25\times r=k\,{{(2.5X)}^{n}}\] or   \[6.25\times k\times {{(X)}^{n}}=k{{(2.5\times X)}^{n}}\] \[\Rightarrow \,\,\,\,\left( \frac{2.5X}{X} \right)=6.25\Rightarrow {{(2.5)}^{n}}={{(2.5)}^{2}}\] \[\therefore \,\,\,n=2\]          


You need to login to perform this action.
You will be redirected in 3 sec spinner