A) \[5\times {{10}^{-11}}Pa\]
B) \[5\times {{10}^{-6}}Pa\]
C) \[1\times {{10}^{-6}}Pa\]
D) \[1\times {{10}^{-11}}Pa\]
Correct Answer: B
Solution :
[b]: Pressure exerted by absorbed light\[=\frac{1}{2}\left( \frac{I}{c} \right)\] Pressure exerted by reflected light Total radiation pressure on the surface is, \[{{P}_{rad}}=\frac{\frac{3}{2}I}{c}=\frac{1.5\times {{10}^{3}}}{3\times {{10}^{8}}}=5\times {{10}^{-6}}Pa\]
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