A) \[10\]
B) \[11\]
C) \[12\]
D) \[13\]
Correct Answer: C
Solution :
[c] \[11=\left| z-\frac{12}{z} \right|\ge \left| z \right|=\frac{12}{\left| z \right|}\] \[\Rightarrow \,\,\,\,{{\left| z \right|}^{2}}-11\left| z \right|-12\le 0\] \[\Rightarrow \,\,\,(|z|+1)\,\,(|z|-12)\le 0\] \[\Rightarrow \,\,\,-1\le \,\,|z|\,\le \,12\] \[\Rightarrow \,\,\,0\le \,\,|z|\,\le \,12\] \[\Rightarrow \,\,\,\,|z-0|\,\le \,12\]
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