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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 13

  • question_answer
    We have three aqueous solutions of NaCI labelled as 'A', '5' and 'C' with concentrations M, 0.01 M and 0.001 M, respectively. The value of vant Hoff factor for these solutions will be in the order

    A) \[{{i}_{A}}<{{i}_{B}}<{{i}_{C}}\]    

    B) \[{{i}_{A}}>{{i}_{B}}>{{i}_{C}}\]

    C) \[{{i}_{A}}={{i}_{B}}={{i}_{C}}\]    

    D) \[{{i}_{A}}<{{i}_{B}}>{{i}_{C}}\]

    Correct Answer: C

    Solution :

    [c]: The value of van?t Hoff factor for the given solutions will be the same, i.e., \[{{i}_{A}}={{i}_{B}}={{i}_{C}}\]due to complete dissociation of NaCI (strong electrolyte) in dilute solutions. On complete dissociation value of i for NaCI is 2.


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