A) \[{{d}^{6}}\](High spin)
B) \[{{d}^{5}}\](Low spin)
C) \[{{d}^{4}}\](Low spin)
D) \[{{d}^{7}}\](High spin)
Correct Answer: B
Solution :
[b]:\[{{d}^{6}}\](High spin);\[t_{2g}^{4}e_{g}^{2}\] \[CFSE=(-0.4\times 4+0.6\times 2){{\Delta }_{0}}=-0.4{{\Delta }_{0}}\] [b] \[{{d}^{5}}\] (Low spin);\[t_{2g}^{5}\] \[CFSE=(-0.4\times 5+0.6\times 0){{\Delta }_{0}}=-2.0{{\Delta }_{0}}\] [c] \[{{d}^{4}}\](Low spin); \[t_{2g}^{4}\] \[CFSE=(-0.4\times 4+0.6\times 0){{\Delta }_{0}}=-1.6{{\Delta }_{0}}\] [d] \[{{d}^{7}}\](High spin);\[t_{2g}^{5}e_{g}^{2}\] \[CFSE=(-0.4\times 5+0.6\times 2){{\Delta }_{0}}=-0.8{{\Delta }_{0}}\] Magnitude of CFSE is maximum for \[{{d}^{5}}\](low spin complex)
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