A) \[Be,\text{ }Mg\]
B) \[Ca,\text{ }Be\]
C) \[Ba,\text{ }Be\]
D) \[Mg,\text{ }Be\]
Correct Answer: D
Solution :
| [d] (1) Carbide of \[Be\]e and \[Al\] with \[{{H}_{2}}O\] gives \[C{{H}_{4}}\]gas. |
| (i) \[B{{e}_{2}}C+4{{H}_{2}}O\xrightarrow{{}}2Be{{(OH)}_{2}}+C{{H}_{4}}\uparrow \] |
| (ii) \[A{{l}_{4}}{{C}_{3}}+12{{H}_{2}}O\xrightarrow[{}]{}4Al\,{{(OH)}_{3}}+3C{{H}_{4}}\uparrow \] |
| (2) Carbides of \[Mg\] with \[{{H}_{2}}O\] gives propyne gas |
| \[M{{g}_{2}}{{C}_{3}}+4{{H}_{2}}O\xrightarrow{{}}2Mg{{(OH)}_{2}}+\underset{\Pr opyne}{\mathop{C{{H}_{3}}C\equiv CH}}\,\] |
| (3) Carbides of \[Ca,\text{ }Sr,\text{ }Ba\]with \[{{H}_{2}}O\] gives acetylene \[(CH\equiv CH)\] gas. |
| \[Ca{{C}_{2}}+{{H}_{2}}O\xrightarrow{{}}Ca{{(OH)}_{2}}+CH\equiv CH.\] |
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