question_answer

If the distance between the planes \[Ax-2y+z=d\] and the plane containing the lines \[\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\] and \[\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\] is \[\sqrt{6},\] then \[|d|\] is

Answer:

6