JEE Main & Advanced Sample Paper JEE Main - Mock Test - 10

  • question_answer
    The length of the latus rectum of the hyperbola \[16{{x}^{2}}-25{{y}^{2}}+400=0\]is

    A) \[\frac{32}{5}\]             

    B) \[\frac{16}{5}\]

    C) \[\frac{25}{4}\] 

    D) \[\frac{25}{2}\]

    Correct Answer: D

    Solution :

    [d]: \[16{{x}^{2}}-25{{y}^{2}}+400=0\] \[\Rightarrow \]\[\frac{{{y}^{2}}}{16}-\frac{{{x}^{2}}}{25}=1\Rightarrow {{a}^{2}}=16,{{b}^{2}}=25\] \[\therefore \]Latus rectum \[=\frac{2{{b}^{2}}}{a}=\frac{50}{4}=\frac{25}{2}\].


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