JEE Main & Advanced Sample Paper JEE Main - Mock Test - 10

  • question_answer
    The reaction conditions leading to the best yields of \[{{C}_{2}}{{H}_{5}}Cl\]are:

    A) \[{{C}_{2}}{{H}_{6}}(excess)+C{{l}_{2}}\xrightarrow{UV\,light}\]

    B) \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow[room\,\,temperature]{dark}\]

    C) \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}(excess)\xrightarrow{UV\,light}\]

    D) \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow{UV\,light}\]

    Correct Answer: A

    Solution :

    \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow{UV\,light}{{C}_{2}}{{H}_{5}}Cl+HCl\]


You need to login to perform this action.
You will be redirected in 3 sec spinner