A) \[8m{{s}^{-1}}\]
B) \[16\,m{{s}^{-1}}\]
C) \[24\,m{{s}^{-1}}\]
D) \[32\,m{{s}^{-1}}\]
Correct Answer: C
Solution :
[c] \[64\frac{4}{3}\pi {{r}^{3}}\Rightarrow \frac{4}{3}\pi {{R}^{3}}\] \[R=4r\] \[{{V}_{t}}=\frac{2}{9}\frac{{{r}^{2}}(\rho -\sigma )}{g}\] \[\frac{V_{t}^{1}}{{{V}_{t}}}=\frac{{{R}^{2}}}{{{r}^{2}}}=\frac{16{{r}^{2}}}{{{r}^{2}}}\Rightarrow \,V_{t}^{1}=\left( 16 \right)\,\left( 1.5 \right)=24\,m{{s}^{-1}}\]
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