A) Optical isomer
B) Chain isomer
C) Positional isome
D) Functional isomer
Correct Answer: B
Solution :
[b]\[Normal\,bu\tan e\Rightarrow {{H}_{3}}C-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\] \[\text{Isobutane}\Rightarrow {{H}_{3}}C-\overset{\overset{C{{H}_{3}}}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{3}}\]You need to login to perform this action.
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