A) 1.6 g
B) 0.1 g
C) 1 g
D) 16 g
Correct Answer: A
Solution :
[a] No. of mole \[=\frac{mass\,\,o\text{f}\,\,\text{substance}}{molecular\,\,mass\,\,o\text{f}\,\,\text{substance}}\] \[0.1=\frac{W}{{{M}_{CH}}_{_{4}}};0.1=\frac{W}{16}\left( \because \,{{M}_{C{{H}_{4}}}}=16 \right)\Rightarrow W=1.6\,gm\]
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