A) \[16\frac{4}{11}\] Minutes past 3
B) \[15\frac{5}{61}\] Minutes past 3
C) \[15\frac{5}{60}\] Minutes to 2
D) \[16\frac{4}{11}\] Minutes to 4
Correct Answer: A
Solution :
[a] Since, in one hour, two hands of a clock coincide only once, so, there will be value. Required time \[T=\frac{2}{11}(H\times 30+A{}^\circ )\] minutes past H. Here H = Initial position of hour hand = 3 (Since 3 o? clock) \[A{}^\circ =\] Required angle = \[0{}^\circ \] (Since it coincides) \[T=\frac{2}{11}(3\times 30+0)\] minutes past 3 \[=16\frac{4}{11}\] minutes past 3.
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