Arrange the following compounds in increasing order of acidity: |
\[CH\equiv CH,C{{H}_{2}}=C{{H}_{2}},ClC{{H}_{2}}C{{H}_{3}},FC{{H}_{2}}C{{H}_{3}},C{{H}_{3}}C{{H}_{3}}\] |
A) \[CH\equiv CH<C{{H}_{2}}=C{{H}_{2}}<C{{H}_{3}}C{{H}_{3}}<ClC{{H}_{2}}C{{H}_{3}}<FC{{H}_{2}}C{{H}_{3}}\]
B) \[C{{H}_{3}}C{{H}_{3}}<C{{H}_{2}}=C{{H}_{2}}<CH\equiv CH<ClC{{H}_{2}}C{{H}_{3}}<FC{{H}_{2}}C{{H}_{3}}\]
C) \[ClC{{H}_{2}}C{{H}_{3}}<FC{{H}_{2}}C{{H}_{3}}<C{{H}_{2}}=C{{H}_{2}}<CH\equiv CH<C{{H}_{3}}C{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{3}}<ClC{{H}_{2}}C{{H}_{3}}<FC{{H}_{2}}C{{H}_{3}}<C{{H}_{2}}=C{{H}_{2}}<CH\equiv CH\]
Correct Answer: D
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