question_answer

Chromium (III) chloride,\[CrC{{l}_{3}}.6HO\], dissolves in water to form a complex species. If a solution prepared by dissolving 0.1 mole of chromium (III) chloride in water is treated with excess silver nitrate solution, 0.2 mole of silver chloride is precipitated. The most probable formula of the complex species present in the solution is

A)  \[{{[Cr{{({{H}_{2}}O)}_{6}}]}^{3+}}\]        

B)  \[{{[Cr{{({{H}_{2}}O)}_{6}}]}^{2+}}\]

C)  \[{{[Cr{{({{H}_{2}}O)}_{4}}C{{l}_{2}}]}^{+}}\]

D)  \[{{[Cr{{({{H}_{2}}O)}_{3}}Cl]}^{2+}}\]