A) 4:5
B) 5:4
C) 2:5
D) 4:10
Correct Answer: B
Solution :
For car, \[K.E.=100J,{{v}_{C}}=v\] \[\text{From K}\text{.E}\text{.=}\frac{1}{2}m{{v}^{2}}\] \[100=\frac{1}{2}{{m}_{c}}{{v}^{2}}\] For bike, \[K.E.=80J,{{v}_{B}}=v\] \[80=\frac{1}{2}{{m}_{B}}{{v}^{2}}\] \[\frac{K.E{{.}_{C}}}{K.E{{.}_{B}}}=\frac{100}{80}=\frac{\frac{1}{2}{{m}_{C}}{{v}^{2}}}{\frac{1}{2}{{m}_{B}}{{v}^{2}}}\] or, \[\]
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