A) 2:5
B) 7:5
C) 4:25
D) 25:4
Correct Answer: A
Solution :
\[Since,K.E=\frac{1}{2}m{{v}^{2}}\] \[{{m}_{1}}=2kg;{{m}_{2}}=5kg\] \[\text{and }{{\text{v}}_{\text{1}}}={{v}_{2}}=v\] Then, \[K.{{E}_{1}}=\frac{1}{2}\times 2\times {{v}^{2}}\] \[K.{{E}_{2}}=\frac{1}{2}\times 5\times {{v}^{2}}\] \[\therefore K.{{E}_{1}}:K.{{E}_{2}}=2:5\]
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