JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Wet Test for Basic Radical

  • question_answer
    Solution of II A group precipitate in dil. \[HN{{O}_{3}}\] when treated with \[N{{H}_{4}}OH\] becomes blue because of the presence of

    A) \[Mg\]

    B) \[Cd\]

    C) \[Bi\]

    D) \[Cu\]

    Correct Answer: D

    Solution :

    \[CuC{{l}_{2}}+2HN{{O}_{3}}\,\to \,Cu{{(N{{O}_{3}})}_{2}}+2HCl\] \[Cu{{(N{{O}_{3}})}_{2}}\text{ reacts with }N{{H}_{4}}OH\text{ and gives}\,Cu(N{{H}_{3}})_{4}^{2+}\,\] which has deep blue colour.


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