A) Lowering \[\left[ O{{H}^{-}} \right]\]
B) Lowering \[\left[ N{{H}_{4}}OH \right]\]
C) Increasing \[\left[ O{{H}^{-}} \right]\]
D) Increasing \[\left[ N{{H}_{4}}OH \right]\]
Correct Answer: A
Solution :
\[N{{H}_{4}}OH~NH_{4}^{+}+O{{H}^{-}}\] \[N{{H}_{4}}Cl\to NH_{4}^{+}+C{{l}^{-}}\] \[N{{H}_{4}}Cl\]Decreases the dissociation of \[N{{H}_{4}}OH\]by common ion effect
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