A) \[Bi{{\left( OH \right)}_{3}}\]
B) \[B{{i}_{2}}{{O}_{3}}\]
C) \[BiOCl\]
D) \[B{{i}_{2}}OC{{l}_{3}}\]
Correct Answer: C
Solution :
\[BiC{{l}_{3}}+{{H}_{2}}O\to \underset{(white\,\,ppt)}{\mathop{BiOCl}}\,+2HCl\]
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