JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Wet Test for Basic Radical

  • question_answer
    A black sulphide is formed by the action of \[{{H}_{2}}S\] on [IIT 1978]

    A) Cupric chloride

    B) Cadmium chloride

    C) Zinc chloride

    D) Sodium chloride

    Correct Answer: A

    Solution :

    \[CuC{{l}_{2}}+{{H}_{2}}S\to \underset{\text{(Black ppt}\text{.)}}{\mathop{CuS\,\,}}\,+2HCl\]


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