A) \[{{K}_{4}}Fe{{(CN)}_{6}}\]
B) \[F{{e}_{4}}{{\left[ Fe{{(CN)}_{6}} \right]}_{3}}\]
C) \[KMn{{O}_{4}}\]
D) \[Fe{{(OH)}_{3}}\]
Correct Answer: B
Solution :
\[4FeC{{l}_{3}}+3{{K}_{4}}\left[ Fe{{(CN)}_{6}} \right]\]\[\to \underset{\begin{smallmatrix} \text{Prussian}\,\, \\ \text{Blue colour} \end{smallmatrix}}{\mathop{F{{e}_{4}}{{\left[ Fe{{(CN)}_{6}} \right]}_{3}}}}\,+12KCl\]
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