A) \[SnS\]
B) \[Sn{{S}_{2}}\]
C) \[S{{n}_{2}}{{S}_{2}}\]
D) \[{{(N{{H}_{4}})}_{2}}Sn{{S}_{3}}\]
Correct Answer: B
Solution :
\[SnS+{{(N{{H}_{4}})}_{2}}{{S}_{2}}\xrightarrow{HCl}{{(N{{H}_{4}})}_{2}}S+Sn{{S}_{2}}\]
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