A) Bromine
B) Mixture of bromine and \[HBr\]
C) \[HBr\]
D) \[N{{O}_{2}}\]
Correct Answer: A
Solution :
\[2KBr+Mn{{O}_{2}}+3{{H}_{2}}S{{O}_{4}}\to MnS{{O}_{4}}+2KHS{{O}_{4}}\]\[+2{{H}_{2}}O+\underset{\begin{smallmatrix} \text{(reddish}\, \\ \text{brown gas)} \end{smallmatrix}}{\mathop{B{{r}_{2}}\uparrow \,\,\,\,\,\,\,}}\,\]
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