A) \[C{{l}^{-}}\]
B) \[{{I}^{-}}\]
C) \[NO_{3}^{-}\]
D) \[{{S}^{2-}}\]
Correct Answer: B
Solution :
As \[C{{l}^{-}}\]is more electronegative than \[B{{r}^{-}}\] and \[{{I}^{-}}\] \[\therefore \] it replaces them from their salt as \[2{{I}^{-}}+C{{l}_{2}}\to {{I}_{2}}+2C{{l}^{-}}\Rightarrow \text{Violet}\ \text{vapour}\] \[2B{{r}^{-}}+C{{l}_{2}}\to B{{r}_{2}}+2C{{l}^{-}}\Rightarrow \text{Brown vapour}\]
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