A) \[{{F}^{-}}\]
B) \[B{{r}^{-}}\]
C) \[CO_{3}^{2-}\]
D) \[PO_{4}^{3-}\]
Correct Answer: A
Solution :
With \[{{F}^{-}}\], no precipitate is obtained because of low lattice energy of AgF, so it remains in ionized state
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