Answer:
The magnifying power of a microscope is defined as the ratio of the angle subtended by the image at the eye and the angle subtended by the object seen directly, when both lie at the least distance of distinct vision. The magnifying power of a compound microscope is given by \[M=\frac{\upsilon }{u}\left( 1+\frac{D}{{{f}_{e}}} \right)=\left( 1-\frac{\upsilon }{{{f}_{0}}} \right)\left( 1+\frac{D}{{{f}_{e}}} \right)\] where \[u\]and \[\upsilon \] are the distances of object and image from the objective lens. The resolving power of a microscope is defined as the reciprocal of the minimum distance (d) between two point objects, which can just be seen through the microscope as separate. \[R.P=\frac{1}{d}=\frac{2\mu \sin \theta }{\lambda }\] where \[\mu \] is the refractive index of the medium between object and objective lens, \[\theta \] is half the angle of cone of light from the point object.
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