A) \[BH_{4}^{-}\] and \[NH_{4}^{+}\]
B) \[PF_{6}^{-}\]and \[S{{F}_{6}}\]
C) \[Si{{F}_{4}}\] and \[S{{F}_{4}}\]
D) \[IO_{3}^{-}\] and \[Xe{{O}_{3}}\]
Correct Answer: C
Solution :
\[Si{{F}_{4}}\] has symmetrical tetrahedral shape which is due to \[s{{p}^{3}}\] hybridization of the central sulphur atom in its excited state configuration. \[S{{F}_{4}}\] has distorted tetrahedral or Sea- Saw geometry which arise due to \[s{{p}^{3}}d\]hybridization of central sulphur atom and due to the presence of lone pair of electron in one of the equatorial hybrid orbital.
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