JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank VSEPR theory

  • question_answer
    The bond angle in ammonia molecule is                [EAMCET 1980]

    A)                 \[{{91}^{o}}{8}'\]             

    B)                 \[{{93}^{o}}3'\]

    C)                 \[{{106}^{o}}45'\]            

    D)                 \[{{109}^{o}}28'\]

    Correct Answer: C

    Solution :

                    In \[N{{H}_{3}},s{{p}^{3}}\]-hybridization is present but bond angle is \[{{106}^{o}}4{5}'\] because Nitrogen has lone pair of electron according to VSEPR theory due to bp-lp repulsion bond angle decreases from \[{{109}^{o}}45'\] to \[{{106}^{o}}4{5}'\].


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