JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    What is the volume of 0.1 N-HCl required to react completely with 1.0 gm of pure calcium carbonate? [DPMT 2004]

    A) \[100\,c{{m}^{3}}\]

    B) \[150\,c{{m}^{3}}\]

    C) \[250\,c{{m}^{3}}\]

    D) \[200\,c{{m}^{3}}\]

    Correct Answer: D

    Solution :

    Given, \[N=0.1,\] w = 1.0 gm, equivalent weight = 50, V = ? \[V=\frac{w\times 1000}{Eq.wt.\times N}=\frac{1\times 1000}{50\times 0.1}=200\ c{{m}^{3}}\]


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