JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    To change the strength of 25 ml of 0.15 M \[HCl\] to 0.1 M the quantity of water that is to be added is [EAMCET 1979]

    A) 37.5 ml

    B) 12.5 ml

    C) 25.0 ml

    D) 18.75 ml

    Correct Answer: B

    Solution :

    \[{{N}_{1}}{{V}_{1}}\ =\ {{N}_{2}}{{V}_{2}}\] \[0.15\times 25=0.1{{V}_{2}}\Rightarrow {{V}_{2}}=37.5\,ml\] Water to be added = 37.5 - 25 = 12.5 ml


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