JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    0.16 gm of a dibasic acid required 25 ml of decinormal \[NaOH\] solution for complete neutralization. The molecular weight of the acid is [CPMT 1989; MP PET 1993]

    A) 32

    B) 64

    C) 128

    D) 256

    Correct Answer: C

    Solution :

    \[\frac{0.16}{x}\ \times \ \frac{1000}{25}\ =\ \frac{1}{10}\] Þ\[\frac{6.4}{x}\ =\ \frac{1}{10}\ \ \ \ \therefore \ x\ =\ 64\] Mol. wt. = 64 × 2 = 128


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