JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    How many grams of \[NaOH\] are equivalent to 100 ml of 0.1 N oxalic acid

    A) 0.2

    B) 2.0

    C) 0.4

    D) 4.0

    Correct Answer: C

    Solution :

    \[N\ =\ \frac{{{W}_{B}}\ \times \ 1000}{\text{Eq}\text{.}wt\text{.}\ \times \ V};\ {{W}_{B}}=\frac{N\times \ Eq.wt\ \times \ V}{1000}\] \[=\frac{0.1\times 40\times 100}{1000}=0.4\]


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