A) 158 gm
B) 31.60 gm
C) 62.0 gm
D) 790 gm
Correct Answer: B
Solution :
In acidic medium 2 molecules of \[KMn{{O}_{4}}\]gives 5 atoms of oxygen \[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+3{{H}_{2}}O+5(O)\] \[2\times 158=\frac{316\times 8}{80}=31.6\]. So, equivalent wt. of \[KMn{{O}_{4}}\] in acidic medium is = 31.6 gm
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