JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    Molecular weight of oxalic acid is 126. The weight of oxalic acid required to neutralise 100 cc of normal solution of \[NaOH\] is  [NCERT 1973]

    A) 6.3 gm

    B) 126 gm

    C) 530 gm

    D) 63 gm

    Correct Answer: A

    Solution :

    \[1\ =\ \frac{x\ \times \ 1000}{63\ \times \ 100}\ \Rightarrow \ x\ =\ 6.3\ gms\]


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