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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    200 ml 0.6 N  \[{{H}_{2}}S{{O}_{4}}\] and 100 ml of \[0.3N\] \[HCl\] are mixed together. Acidic normality of the resultant solution is [DPMT 1991]

    A) 0.5 N

    B) 0.9 N

    C) 0.3 N

    D) 0.6 N

    Correct Answer: A

    Solution :

    \[{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}~=~{{N}_{3}}{{V}_{3}}\]        \[200\times 0.6+100\times 0.3={{N}_{3}}{{V}_{3}}\,\text{and}{{V}_{3}}={{V}_{2}}+\,{{V}_{1}}\]\[=\ 300\ ml\]       \[\therefore \ {{N}_{3}}\ =\ 0.5\ N\]


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