JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    15 ml of 0.2 N alkali is required to complete neutralization of 30 ml acid solution. Concentration of the acid solution is [NCERT 1985; CPMT 1986]

    A) 0.1 N

    B) 0.3 N

    C) 0.15 N

    D) 0.4 N

    Correct Answer: A

    Solution :

    \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[15\times 0.2\text{ }=\text{ }30\times x\] \[\therefore \ x\ =\ 0.1\ N\]


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