JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    8 ml of \[\frac{N}{10}HCl\] are required to neutralize 20 ml solution of \[N{{a}_{2}}C{{O}_{3}}\] in water. Normality of \[N{{a}_{2}}C{{O}_{3}}\] solution is

    A) 0.40 N

    B) 0.040 N

    C) 4.0 N

    D) 1.4 N

    Correct Answer: B

    Solution :

    N1V1 = N2V2  \[\Rightarrow \frac{1}{10}\times 8={{N}_{2}}\times 20,\]  \[\therefore {{N}_{2}}=0.04N\]


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