A) Amplitude of the vibrations
B) Material of the wire
C) Stretching force
D) Diameter of the wires
Correct Answer: A
Solution :
Change in amplitude does not produce change in frequency, \[\left( n=\frac{1}{2l}\sqrt{\frac{T}{\pi {{r}^{2}}\rho }} \right)\].You need to login to perform this action.
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